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Résoudre dans ℝ les équations suivantes :
-
$\dfrac x 8 = \dfrac 5 7$;
Corrigé
\begin{flalign*}
\dfrac x 8 &= \dfrac 5 7&
\\ \iff
x &= 8 \times \dfrac 5 7&
\\ \iff
x&= \dfrac{40} 7.&
\\
S &= \left\{\dfrac{40} 7\right\}.&
\end{flalign*}
-
$\dfrac{2x - 3} 5 = \dfrac 6 7$;
Corrigé
\begin{flalign*}
\dfrac{2x - 3} 5 &= \dfrac 6 7&
\\ \iff
2x - 3 &= 5\times \dfrac 6 7&
\\ \iff
2x - 3 &=\dfrac{30} 7&
\\ \iff
2x &=\dfrac{30} 7 + 3&
\\ \iff
2x &= \dfrac{30} 7 + \dfrac{21} 7&
\\ \iff
2x &=\dfrac{51} 7&
\\ \iff
x &=\dfrac 1 2\times \dfrac{51} 7&
\\ \iff
x &= \dfrac{51}{14}&
\\
S &=\left\{\dfrac{51}{14}\right\}.&
\end{flalign*}
-
$\dfrac{4x - 3} 2 = \dfrac{2x + 5} 3$.
Corrigé
\begin{flalign*}
\dfrac{4x - 3} 2 &= \dfrac{2x + 5} 3&
\\ \iff
3(4x - 3) &= 2(2x+5)&
\\ \iff
12x - 9 &= 4x + 10&
\\ \iff
12x - 4x &= 10 + 9
\\ \iff
8x &= 19&
\\ \iff
x &=\dfrac{19} 8&
\\
S&=\left\{\dfrac{19} 8\right\}&.
\end{flalign*}
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