Corrigé du 17 P. 44
retour
\[\begin{aligned} u_0 &= 3\;;& \\ u_1 &= u_0 + r = 3 + 7 = 10\;;& \\ u_2 &= u_1 + r = 10+7 = 17\;;& \\ u_3 &= u_2 + r = 17 + 7 = 24.& \end{aligned}\]