Corrigé du 67 P. 300

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a. \[\ln\left(16\right) = \ln\left(2^4\right) = 4\ln(2).\]
b. \[\ln\left(\dfrac 1 4\right) = -\ln(4) = -\ln\left(2^2\right) = -2\ln(2).\] c. \[\ln\left(\sqrt{64}\right) = \ln(8) = \ln\left(2^3\right) = 3\ln(2).\] d. \[\ln\left(\dfrac 1 {256}\right) = -\ln\left(256\right) =-\ln\left(2^8\right) = -8\ln(2).\]

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